Which of the following is the correct option for free expansion of an ideal gas under adiabatic condition?

Question

Which of the following is the correct option for free expansion of an ideal gas under adiabatic condition? (A) q=0, Δ T≠0, W=0 (B) q=0, Δ T≠0, W≠0 (C) q=0, Δ T=0, W=0 (D) q=0, Δ T=0, W≠0

Tardigrade Admin · Accepted Answer

For the free expansion of an ideal gas, the opposing force is zero, hence work done = 0. Δ U=q+w, w=0, hence Δ U=q But the process is adiabatic, hence q = 0 ∴ q=0, Δ T=0, W=0

Q. Which of the following is the correct option for free expansion of an ideal gas under adiabatic condition?

$q = 0, Δ T \neq = 0, W = 0$

$q = 0, Δ T \neq = 0, W \neq = 0$

$q = 0, Δ T = 0, W = 0$

$q = 0, Δ T = 0, W \neq = 0$

For the free expansion of an ideal gas, the opposing force is zero, hence work done = 0.
$Δ U = q + w, w = 0, h e n ce Δ U = q$
But the process is adiabatic, hence q = 0
$∴ q = 0, Δ T = 0, W = 0$

Q. Which of the following is the correct option for free expansion of an ideal gas under adiabatic condition?

q=0,ΔT=0,W=0

q=0,ΔT=0,W=0

q=0,ΔT=0,W=0

q=0,ΔT=0,W=0

For the free expansion of an ideal gas, the opposing force is zero, hence work done = 0. ΔU=q+w,w=0,henceΔU=q But the process is adiabatic, hence q = 0 ∴q=0,ΔT=0,W=0

$q = 0, Δ T \neq = 0, W = 0$

$q = 0, Δ T \neq = 0, W \neq = 0$

$q = 0, Δ T = 0, W = 0$

$q = 0, Δ T = 0, W \neq = 0$

For the free expansion of an ideal gas, the opposing force is zero, hence work done = 0.
$Δ U = q + w, w = 0, h e n ce Δ U = q$
But the process is adiabatic, hence q = 0
$∴ q = 0, Δ T = 0, W = 0$