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Q. Which of the following is the correct option for free expansion of an ideal gas under adiabatic condition?

WBJEEWBJEE 2016

Solution:

For the free expansion of an ideal gas, the opposing force is zero, hence work done = 0.
$\Delta U=q+w, w=0, hence \Delta U=q$
But the process is adiabatic, hence q = 0
$\therefore q=0, \Delta T=0, W=0$