Which of the following have been arranged in decreasing order of oxidation number of sulphur?

Question

Which of the following have been arranged in decreasing order of oxidation number of sulphur? (A) H2SO4>SO2>H2S>H2S2O8 (B) Na2S4O6>H2S2O7>Na2S2O3>S8 (C) H2SO5>H2SO3>SCl2>H2 (D) SO22 +>SO42 ->SO32 ->HSO4-

Tardigrade Admin · Accepted Answer

Compound Oxidation state H2SO5 +6 H2SO3 +4 SCl2 +2 H2S -2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-7li2dn4vpkv5.png" />

Compound	Oxidation state
$H_{2} S O_{5}$	$+ 6$
$H_{2} S O_{3}$	$+ 4$
$SC l_{2}$	$+ 2$
$H_{2} S$	$- 2$

Q. Which of the following have been arranged in decreasing order of oxidation number of sulphur?

$H_{2} S O_{4} > S O_{2} > H_{2} S > H_{2} S_{2} O_{8}$

$N a_{2} S_{4} O_{6} > H_{2} S_{2} O_{7} > N a_{2} S_{2} O_{3} > S_{8}$

$H_{2} S O_{5} > H_{2} S O_{3} > SC l_{2} > H_{2}$

$S O_{2}^{2 +} > S O_{4}^{2 -} > S O_{3}^{2 -} > H S O_{4}^{-}$

Compound Oxidation state

$H_{2} S O_{5}$ $+ 6$

$H_{2} S O_{3}$ $+ 4$

$SC l_{2}$ $+ 2$

$H_{2} S$ $- 2$

Q. Which of the following have been arranged in decreasing order of oxidation number of sulphur?

H2​SO4​>SO2​>H2​S>H2​S2​O8​

Na2​S4​O6​>H2​S2​O7​>Na2​S2​O3​>S8​

H2​SO5​>H2​SO3​>SCl2​>H2​

SO22+​>SO42−​>SO32−​>HSO4−​

Compound Oxidation state H2​SO5​ +6 H2​SO3​ +4 SCl2​ +2 H2​S −2

$H_{2} S O_{4} > S O_{2} > H_{2} S > H_{2} S_{2} O_{8}$

$N a_{2} S_{4} O_{6} > H_{2} S_{2} O_{7} > N a_{2} S_{2} O_{3} > S_{8}$

$H_{2} S O_{5} > H_{2} S O_{3} > SC l_{2} > H_{2}$

$S O_{2}^{2 +} > S O_{4}^{2 -} > S O_{3}^{2 -} > H S O_{4}^{-}$

Compound Oxidation state

$H_{2} S O_{5}$ $+ 6$

$H_{2} S O_{3}$ $+ 4$

$SC l_{2}$ $+ 2$

$H_{2} S$ $- 2$