Question

Which of the following have been arranged in decreasing order of oxidation number of sulphur?

• A. $H_{2}SO_{4}>SO_{2}>H_{2}S>H_{2}S_{2}O_{8}$
• B. $Na_{2}S_{4}O_{6}>H_{2}S_{2}O_{7}>Na_{2}S_{2}O_{3}>S_{8}$
• C. $H_{2}SO_{5}>H_{2}SO_{3}>SCl_{2}>H_{2}$
• D. $SO_{2}^{2 +}>SO_{4}^{2 -}>SO_{3}^{2 -}>HSO_{4}^{-}$

Answer 1

Answer: (C)

Compound	Oxidation state
$H_{2}SO_{5}$	$+6$
$H_{2}SO_{3}$	$+4$
$SCl_{2}$	$+2$
$H_{2}S$	$-2$