Which of the following expressions represents the relation between orbital magnetic moment and orbital angular momentum of an electron ?

Question

Which of the following expressions represents the relation between orbital magnetic moment and orbital angular momentum of an electron ? (A)  vec μorb=(2me/e)Lorb  (B)  vec μorb=-2me Lorb  (C)  vec μorb=-(e/2me)Lorb  (D)  vec μorb=(e/2me)Lorb

Tardigrade Admin · Accepted Answer

When an electron is revolving in orbit then orbital magnetic moment and orbital angular momentum are in opposite direction also

∣ μ_{or b} ∣ = \frac{e h}{4 π m _{e}}

and

∣ L_{or b} ∣ = \frac{h}{2 π}

(For

n = 1

)

∴

μ_{or b} = - \frac{e}{2 m _{e}} L_{or b}

Q. Which of the following expressions represents the relation between orbital magnetic moment and orbital angular momentum of an electron ?

$μ_{or b} = \frac{2 m _{e}}{e} L_{or b}$

$μ_{or b} = - 2 m_{e} L_{or b}$

$μ_{or b} = - \frac{e}{2 m _{e}} L_{or b}$

$μ_{or b} = \frac{e}{2 m _{e}} L_{or b}$

When an electron is revolving in orbit then orbital magnetic moment and orbital angular momentum are in opposite direction also
$∣ μ_{or b} ∣ = \frac{e h}{4 π m _{e}}$
and $∣ L_{or b} ∣ = \frac{h}{2 π}$ (For $n = 1$ )
$∴$ $μ_{or b} = - \frac{e}{2 m _{e}} L_{or b}$

Q. Which of the following expressions represents the relation between orbital magnetic moment and orbital angular momentum of an electron ?

μ​orb​=e2me​​Lorb​

μ​orb​=−2me​Lorb​

μ​orb​=−2me​e​Lorb​

μ​orb​=2me​e​Lorb​

When an electron is revolving in orbit then orbital magnetic moment and orbital angular momentum are in opposite direction also ∣μorb​∣=4πme​eh​ and ∣Lorb​∣=2πh​ (For n=1) ∴ μorb​=−2me​e​Lorb​

$μ_{or b} = \frac{2 m _{e}}{e} L_{or b}$

$μ_{or b} = - 2 m_{e} L_{or b}$

$μ_{or b} = - \frac{e}{2 m _{e}} L_{or b}$

$μ_{or b} = \frac{e}{2 m _{e}} L_{or b}$

When an electron is revolving in orbit then orbital magnetic moment and orbital angular momentum are in opposite direction also
$∣ μ_{or b} ∣ = \frac{e h}{4 π m _{e}}$
and $∣ L_{or b} ∣ = \frac{h}{2 π}$ (For $n = 1$ )
$∴$ $μ_{or b} = - \frac{e}{2 m _{e}} L_{or b}$