Question

Which of the following does not/do not represent the correct equivalent mass of $C{r}_2{O}_7^{2-}$ in the reaction
$C{r}_2{O}_7^{2-}+14H^{+}+6e^{-}\to 2C{r}^{3+}+7H_{2}O$ ?

• A. The molar mass of dichromate
• B. One third of the molar mass of dichromate
• C. One sixth of the molar mass of dichromate
• D. One half of the molar mass of dichromate

Answer 1

Answer: (A), (B), (D)

$\therefore E_{C{r}_2{O}_7^{2-}}=\frac{{}^{M}C{r}_2{O}_7^{2-}}{6}$

$\left[C{r}_2^{6+}⟶2C{r}^{3+}+6e^{-}\right]$