Question

$RCON{H}_2$ is converted into $RN{H}_2$ by means of Hofmann's bromamide degradation.

In this reaction, $RCONHBr$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann's degradation reaction is an intramolecular reaction. $(2006,3\times 4M=12M)$
Which is the rate determining step in Hofmann's bromamide degradation?

• A. Formation of (i)
• B. Formation of (ii)
• C. Formation of (iii)
• D. Formation of (iv)

Answer 1

Answer: (D)

Rearrangement of (iii) to (iv) is the rate determining step