Question

$RCONH _{2}$ is converted into $RNH _{2}$ by means of Hofmann's bromamide degradation.

In this reaction, $RCONHBr $ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann's degradation reaction is an intramolecular reaction. $(2006,3 \times 4 M =12 M )$
Which is the rate determining step in Hofmann's bromamide degradation?

• A. Formation of (i)
• B. Formation of (ii)
• C. Formation of (iii)
• D. Formation of (iv)

Answer 1

Answer: (D)

Rearrangement of (iii) to (iv) is the rate determining step