Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?

Question

Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide? (A) Tertiary butyl chloride (B) Neopentane (C) Isohexane (D) Neohexane

Tardigrade Admin · Accepted Answer

Molar mass = 72 = CnH2n + 2 = 12n + (2n + 2) n = 5 Thus, hydrocarbon is C5H12 . Since, it gives only single C5H11C1. This suggests that C5H12 is symmetrical. Hence, it is containing all 12 equivalent H-atoms. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a8060b3960d913af4a59651bd515e8da-.jpeg" />

Q. Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?

Tertiary butyl chloride

Neopentane

Isohexane

Neohexane

Molar mass $= 72 = C_{n} H_{2 n + 2} = 12 n + (2 n + 2) n = 5$
Thus, hydrocarbon is $C_{5} H_{12}$
. Since, it gives only single $C_{5} H_{11} C 1$ . This suggests that $C_{5} H_{12}$ is symmetrical.
Hence, it is containing all 12 equivalent H-atoms.

Q. Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?

Tertiary butyl chloride

Neopentane

Isohexane

Neohexane

Molar mass =72=Cn​H2n+2​=12n+(2n+2)n=5 Thus, hydrocarbon is C5​H12​ . Since, it gives only single C5​H11​C1. This suggests that C5​H12​ is symmetrical. Hence, it is containing all 12 equivalent H-atoms.

Molar mass $= 72 = C_{n} H_{2 n + 2} = 12 n + (2 n + 2) n = 5$
Thus, hydrocarbon is $C_{5} H_{12}$
. Since, it gives only single $C_{5} H_{11} C 1$ . This suggests that $C_{5} H_{12}$ is symmetrical.
Hence, it is containing all 12 equivalent H-atoms.