Thank you for reporting, we will resolve it shortly
Q.
Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?
Haloalkanes and Haloarenes
Solution:
Molar mass $= 72 = C_{n}H_{2n + 2} = 12n + (2n + 2) n = 5$
Thus, hydrocarbon is $C_{5}H_{12}$
.
Since, it gives only single $C_{5}H_{11}C1$. This suggests that $C_{5}H_{12}$ is symmetrical.
Hence, it is containing all 12 equivalent H-atoms.
