Question

When zinc reacts with dilute nitric acid, nitrous oxide is produced. What mass of the gas is evolved by treating $325g$ zinc with excess of nitric acid?

• A. $44g$
• B. $66g$
• C. $55g$
• D. $33g$

Answer 1

Answer: (C)

$\therefore$ The gas evolved by treating $260gZn$ with excess of nitric acid $=44g$
$\therefore$ The gas evolved by treating $325g$ of $Zn$ with excess of nitric acid
$=(44/260)\times 325=55g$