Question

When zinc reacts with dilute nitric acid, nitrous oxide is produced. What mass of the gas is evolved by treating $325\, g$ zinc with excess of nitric acid?

• A. $44\, g$
• B. $66\, g$
• C. $55\, g$
• D. $33\, g$

Answer 1

Answer: (C)

$\therefore$ The gas evolved by treating $260\, g\, Zn$ with excess of nitric acid $=44\, g$
$\therefore$ The gas evolved by treating $325\, g$ of $Zn$ with excess of nitric acid
$=(44 / 260) \times 325=55\, g$