Question

When xenon hexafluoride is treated with ${\text{AsF}}_{\text{5}}$ to form an ionic compound, the hybridisation of $\text{Xe}$ and $\text{As}$ will be respectively

• A. ${\text{sp}}^{\text{3}}{\text{d}}^{\text{2}}{\text{, sp}}^{\text{3}}\text{d}$
• B. ${\text{sp}}^{\text{3}}{\text{d, sp}}^{\text{3}}{\text{d}}^{\text{2}}$
• C. ${\text{sp}}^{\text{3}}{\text{d}}^{\text{3}}{\text{, sp}}^{\text{3}}{\text{d}}^{\text{2}}$
• D. ${\text{sp}}^{\text{3}}{\text{d}}^{\text{2}}{\text{, sp}}^{\text{3}}{\text{d}}^{\text{2}}$

Answer 1

Answer: (D)

${\text{XeF}}_{\text{6}}\text{+}{\text{AsF}}_{\text{5}}\to {\text{[XeF}}_{\text{5}}{\text{]}}^{\text{+}}{\text{[AsF}}_{\text{6}}{\text{]}}^{-}$