Question

When xenon hexafluoride is treated with $\text{AsF}_{\text{5}}$ to form an ionic compound, the hybridisation of $\text{Xe}$ and $\text{As}$ will be respectively

• A. $\text{sp}^{\text{3}} \text{d}^{\text{2}} \text{, sp}^{\text{3}} \text{d}$
• B. $\text{sp}^{\text{3}} \text{d, sp}^{\text{3}} \text{d}^{\text{2}}$
• C. $\text{sp}^{\text{3}} \text{d}^{\text{3}} \text{, sp}^{\text{3}} \text{d}^{\text{2}}$
• D. $\text{sp}^{\text{3}} \text{d}^{\text{2}} \text{, sp}^{\text{3}} \text{d}^{\text{2}}$

Answer 1

Answer: (D)

$\text{XeF}_{\text{6}} \, \text{+} \, \text{AsF}_{\text{5}} \rightarrow \text{[XeF}_{\text{5}} \text{]}^{\text{+}} \, \text{[AsF}_{\text{6}} \text{]}^{-}$