When tetrahydrafuran is treated with excess HI, the product formed is

Question

When tetrahydrafuran is treated with excess HI, the product formed is (A) 1, 4-diiodobutane (B) 1, 4-butanediol (C) 2-iodotetrahydrofuran (D) 4-iodo-1-butanol

Tardigrade Admin · Accepted Answer

Tetrahydrofuran when treated with excess HI, gives 1, 4-diiodobutane.

Q. When tetrahydrafuran is treated with excess $H I,$ the product formed is

$1, 4$ -diiodobutane

$1, 4$ -butanediol

$2$ -iodotetrahydrofuran

$4$ -iodo- $1$ -butanol

$2, 5$ -diiodotetrahydrofuran

Tetrahydrofuran when treated with excess $H I,$ gives 1, 4-diiodobutane.

Q. When tetrahydrafuran is treated with excess HI, the product formed is

1,4-diiodobutane

1,4-butanediol

2-iodotetrahydrofuran

4-iodo-1-butanol

2,5-diiodotetrahydrofuran