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Chemistry
When tetrahydrafuran is treated with excess HI, the product formed is
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Q. When tetrahydrafuran is treated with excess $ HI, $ the product formed is
KEAM
KEAM 2009
Haloalkanes and Haloarenes
A
$1, 4$-diiodobutane
81%
B
$1, 4$-butanediol
4%
C
$2$-iodotetrahydrofuran
7%
D
$4$-iodo-$1$-butanol
3%
E
$2, 5$-diiodotetrahydrofuran
3%
Solution:
Tetrahydrofuran when treated with excess $ HI, $ gives 1, 4-diiodobutane.