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Question
Chemistry
When sulphur dioxide is passed in an acidified K2Cr2O7 solution, the oxidation state of sulphur is changed from
Q. When sulphur dioxide is passed in an acidified
K
2
C
r
2
O
7
solution, the oxidation state of sulphur is changed from
6398
206
KCET
KCET 2008
The d-and f-Block Elements
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A
+
4
to
0
12%
B
+
4
to
+
2
19%
C
+
4
to
+
6
58%
D
+
6
to
+
4
11%
Solution:
Acidified
K
22
C
r
2
O
7
solution oxidises
S
O
2
into
C
r
2
(
S
O
4
)
3
.
3
SO
2
+
+4
K
2
C
r
2
O
7
+
+
H
2
S
O
4
⟶
K
2
S
O
4
+
C
r
2
(
S
+
6
O
4
)
3
+
H
2
O
Hence, oxidation state of sulphur changes from
+
4
to
+
6.