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  4. When sulphur dioxide is passed in an acidified K2Cr2O7 solution, the oxidation state of sulphur is changed from

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Q. When sulphur dioxide is passed in an acidified $K_2Cr_2O_7$ solution, the oxidation state of sulphur is changed from

KCETKCET 2008The d-and f-Block Elements

Solution:

Acidified $K_{22}Cr_2O_7$ solution oxidises $ SO_{2}$ into $Cr_2(SO_4)_3$.

$ \overset{\text{+4 }}{{3SO2 } + } { K_2Cr_2O_7 + + H_2SO_4 \longrightarrow K_2SO_4 } +Cr_2\overset{+6}{(S}O_4)_3 + H_2O$

Hence, oxidation state of sulphur changes from $+ 4$ to $+ 6.$