When plate voltage in diode valve is increased from 100 V to 150 V then plate current increases from 7.5 mA to 12 mA. The dynamic plate resistance will be

Question

When plate voltage in diode valve is increased from 100 V to 150 V then plate current increases from 7.5 mA to 12 mA. The dynamic plate resistance will be (A) 10 kΩ (B) 13 kΩ (C) 15 kΩ (D) 11.1 kΩ

Tardigrade Admin · Accepted Answer

rp=(Δ Vp/Δ Ip) = (150-100/(12-7.5)×10-3)=11.1 kΩ

Q. When plate voltage in diode valve is increased from $100 V$ to $150 V$ then plate current increases from $7.5 m A$ to $12 m A$ . The dynamic plate resistance will be

$10 k Ω$

$13 k Ω$

$15 k Ω$

$11.1 k Ω$

$r_{p} = \frac{Δ V _{p}}{Δ I _{p}} = \frac{150 - 100}{( 12 - 7.5 ) \times 1 0 ^{- 3}} = 11.1 k Ω$

Q. When plate voltage in diode valve is increased from 100V to 150V then plate current increases from 7.5mA to 12mA. The dynamic plate resistance will be

10kΩ

13kΩ

15kΩ

11.1kΩ