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  4. When plate voltage in diode valve is increased from 100 V to 150 V then plate current increases from 7.5 mA to 12 mA. The dynamic plate resistance will be

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Q. When plate voltage in diode valve is increased from $100\, V$ to $150\, V$ then plate current increases from $7.5\, mA$ to $12\, mA$. The dynamic plate resistance will be

JIPMERJIPMER 2013Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$r_{p}=\frac{\Delta V_{p}}{\Delta I_{p}} = \frac{150-100}{\left(12-7.5\right)\times10^{-3}}=11.1 k\Omega$