When PCl5 reacts with sulphuric acid, sulphuryl chloride (SO2Cl2) is formed as the final product. This shows that sulphuric acid:

Question

When PCl5 reacts with sulphuric acid, sulphuryl chloride (SO2Cl2) is formed as the final product. This shows that sulphuric acid: (A) has two hydroxyl groups in its structure (B) is a derivative of sulphur dioxide (C) is a dibasic acid (D) has greater affinity for water

Tardigrade Admin · Accepted Answer

PCl 5 attacks - OH group and replace it by - Cl group. Hence, reaction of PCl 5 with H 2 SO 4 shows the presence of 2 - OH groups in H 2 SO 4

Q. When $PC l_{5}$ reacts with sulphuric acid, sulphuryl chloride $(S O_{2} C l_{2})$ is formed as the final product. This shows that sulphuric acid:

has two hydroxyl groups in its structure

is a derivative of sulphur dioxide

is a dibasic acid

has greater affinity for water

$PC l_{5}$ attacks - OH group and replace it by $- Cl$ group. Hence, reaction of $PC l_{5}$ with $H_{2} S O_{4}$ shows the presence of 2 $- O H$ groups in $H_{2} S O_{4}$

Q. When PCl5​ reacts with sulphuric acid, sulphuryl chloride (SO2​Cl2​) is formed as the final product. This shows that sulphuric acid: