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  4. When PCl5 reacts with sulphuric acid, sulphuryl chloride (SO2Cl2) is formed as the final product. This shows that sulphuric acid:

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Q. When $PCl_{5}$ reacts with sulphuric acid, sulphuryl chloride $ (SO_{2}Cl_{2})$ is formed as the final product. This shows that sulphuric acid:

ManipalManipal 2003The p-Block Elements - Part2

Solution:

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$PCl _{5}$ attacks - OH group and replace it by $- Cl$ group. Hence, reaction of $PCl _{5}$ with $H _{2} SO _{4}$ shows the presence of 2 $- OH$ groups in $H _{2} SO _{4}$