When P C l5 reacts with sulphuric acid, sulphuryl chloride (S O2 C l2) is formed as the final product. This shows that sulphuric acid:

Question

When P C l5 reacts with sulphuric acid, sulphuryl chloride (S O2 C l2) is formed as the final product. This shows that sulphuric acid: (A) has two hydroxyl groups in its structure (B) is a derivative of sulphur dioxide (C) is a dibasic acid (D) has greater affinity for water

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fdaad8ebfeb50b376bf5ae94eb8588c4-.png" /> attacks -O H group and replace it by -C l group. Hence, reaction of P C l5 with H 2 SO 4 shows the presence of 2- OH groups in H 2 SO 4.

Q. When $PC l_{5}$ reacts with sulphuric acid, sulphuryl chloride $(S O_{2} C l_{2})$ is formed as the final product. This shows that sulphuric acid:

has two hydroxyl groups in its structure

is a derivative of sulphur dioxide

is a dibasic acid

has greater affinity for water

attacks $- O H$ group and replace it by $- Cl$ group.
Hence, reaction of $PC l_{5}$ with $H_{2} S O_{4}$ shows the presence of $2 - O H$ groups in $H_{2} S O_{4}$ .

Q. When PCl5​ reacts with sulphuric acid, sulphuryl chloride (SO2​Cl2​) is formed as the final product. This shows that sulphuric acid: