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Q.
When $P C l_{5}$ reacts with sulphuric acid, sulphuryl chloride $\left(S O_{2} C l_{2}\right)$ is formed as the final product. This shows that sulphuric acid:
Haryana PMTHaryana PMT 2004
Solution:
attacks $-O H$ group and replace it by $-C l$ group.
Hence, reaction of $P C l_{5}$ with $H _{2} SO _{4}$ shows the presence of $2- OH$ groups in $H _{2} SO _{4}$.