When only a little quantity of HgCl2 (s) is added to excess Kl(aq) to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing)

Question

When only a little quantity of HgCl2 (s) is added to excess Kl(aq) to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing) (A) Its boiling and freezing points remain same (B) Its boiling point is lowered (C) Its vapour pressure become lower (D) Its boiling point is raised

Tardigrade Admin · Accepted Answer

Due to this addition a complex [HgI4]2- will get formed as follows Hg2++4I- ⇒ [HgI4]2- or Hg2++2Cl-+4I- leftharpoons [HgI4]2-+2Cl- on adding we can see that 4I- ions are consumed but resultant number of particles are three Hence boiling point gets decreased freezing point gets increased

Q. When only a little quantity of HgCl2​ (s) is added to excess Kl(aq) to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing)

Its boiling and freezing points remain same

Its boiling point is lowered

Its vapour pressure become lower

Its boiling point is raised

Q. When only a little quantity of $H g C l_{2}$ (s) is added to excess $K l (a q)$ to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing)