1. Tardigrade
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  3. Chemistry
  4. When only a little quantity of HgCl2 (s) is added to excess Kl(aq) to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing)

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Q. When only a little quantity of $HgCl_{2}$ (s) is added to excess $Kl(aq)$ to obtain a clear solution, which of the following is true for this solution? (no volume change on mixing)

Solutions

Solution:

Due to this addition a complex $[HgI_{4}]^{2-}$ will get formed as follows
$Hg^{2+}+4I^{-} \Rightarrow [HgI_{4}]^{2-}$
or $Hg^{2+}+2Cl^{-}+4I^{-} \rightleftharpoons [HgI_{4}]^{2-}+2Cl^{-}$
on adding we can see that $4I^{-}$ ions are consumed but resultant number of particles are three
Hence boiling point gets decreased
freezing point gets increased