When one mole of each of the following complexes is treated with excess of AgNO3, which will give maximum amount of AgCl ?

Question

When one mole of each of the following complexes is treated with excess of AgNO3, which will give maximum amount of AgCl ? (A) [Co (NH3)6]Cl3 (B) [Co (NH3)5Cl]Cl2 (C) [Co (NH3)4 Cl2]Cl (D) [Co (NH3)3Cl3]

Tardigrade Admin · Accepted Answer

In coordination compounds, the counter ions can react to give another product but the complex ion will not split in a solution.
Here, when one mole of a complex given when reacted with

A g N O_{3}

then the maximum counter ion compound will give the maximum amount of

A g Cl

.
Hence,

[C o (N H_{3})_{6}] C l_{3}

having a maximum number of

3

counter ions in the given options will produce more amount of

A g Cl

.

[C o (N H_{3})_{6}] C l_{3} \to [C o (N H_{3})_{6}]^{3 +} (a q) + 3 C l^{-} (a q)

A g N O_{3} + C l^{-} (a q) \to A g Cl + N O_{3}^{-} (a q)

Q. When one mole of each of the following complexes is treated with excess of $A g N O_{3}$ , which will give maximum amount of $A g Cl$ ?

$[C o (N H_{3})_{6}] C l_{3}$

$[C o (N H_{3})_{5} Cl] C l_{2}$

$[C o (N H_{3})_{4} C l_{2}] Cl$

$[C o (N H_{3})_{3} C l_{3}]$

Q. When one mole of each of the following complexes is treated with excess of AgNO3​, which will give maximum amount of AgCl ?

[Co(NH3​)6​]Cl3​

[Co(NH3​)5​Cl]Cl2​

[Co(NH3​)4​Cl2​]Cl

[Co(NH3​)3​Cl3​]

Q. When one mole of each of the following complexes is treated with excess of $A g N O_{3}$ , which will give maximum amount of $A g Cl$ ?

$[C o (N H_{3})_{6}] C l_{3}$

$[C o (N H_{3})_{5} Cl] C l_{2}$

$[C o (N H_{3})_{4} C l_{2}] Cl$

$[C o (N H_{3})_{3} C l_{3}]$