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Q.
When one mole of each of the following complexes is treated with excess of $AgNO_{3}$, which will give maximum amount of $AgCl$ ?
Coordination Compounds
Solution:
In coordination compounds, the counter ions can react to give another product but the complex ion will not split in a solution.
Here, when one mole of a complex given when reacted with $AgNO _{3}$ then the maximum counter ion compound will give the maximum amount of $AgCl$.
Hence, $\left[ Co \left( NH _{3}\right)_{6}\right] Cl _{3}$ having a maximum number of $3$ counter ions in the given options will produce more amount of $AgCl$.
$\left[ Co \left( NH _{3}\right)_{6}\right] Cl _{3} \rightarrow\left[ Co \left( NH _{3}\right)_{6}\right]^{3+}( aq )+3 Cl ^{-}( aq )$
$AgNO _{3}+ Cl ^{-}( aq ) \rightarrow AgCl + NO _{3}^{-}( aq )$