When mercuric iodide is added to the aqueous solution of potassium iodide then

Question

When mercuric iodide is added to the aqueous solution of potassium iodide then (A) freezing point is raised (B) freezing point is lowered (C) freezing point does not change (D) boiling point does not change

Tardigrade Admin · Accepted Answer

When we add HgI2,a complex K2[HgI4] is formed 2KI + HgI2 → K2[HgI4] It results in a decrease in number of moles of particles, because of it Δ Tf increases.

Q. When mercuric iodide is added to the aqueous solution of potassium iodide then

freezing point is raised

freezing point is lowered

freezing point does not change

boiling point does not change

When we add $H g I_{2}$ ,a complex $K_{2} [H g I_{4}]$ is formed
$2 K I + H g I_{2} \to K_{2} [H g I_{4}]$
It results in a decrease in number of moles of particles, because of it $Δ T_{f}$ increases.

Q. When mercuric iodide is added to the aqueous solution of potassium iodide then

freezing point is raised

freezing point is lowered

freezing point does not change

boiling point does not change

When we add HgI2​,a complex K2​[HgI4​] is formed 2KI+HgI2​→K2​[HgI4​] It results in a decrease in number of moles of particles, because of it ΔTf​ increases.

When we add $H g I_{2}$ ,a complex $K_{2} [H g I_{4}]$ is formed
$2 K I + H g I_{2} \to K_{2} [H g I_{4}]$
It results in a decrease in number of moles of particles, because of it $Δ T_{f}$ increases.