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Q.
When mercuric iodide is added to the aqueous solution of potassium iodide then
Solutions
Solution:
When we add $HgI_{2}$,a complex $K_{2}[HgI_{4}]$ is formed
$2KI + HgI_{2} \to K_{2}[HgI_{4}]$
It results in a decrease in number of moles of particles, because of it $\Delta T_{f}$ increases.