When KMnO4 reacts with oxalic acid and HCl separately in acidic medium, Then KMnO4 is convert into Mn2 +,C2O4- 2 into CO2 and Cl- into Cl2 . The moles ratio of [MnO4- 2: C2 O4- 2] and [MnO4- 2: HCl] are respective balanced chemical equations are, respectively.

Question

When KMnO4 reacts with oxalic acid and HCl separately in acidic medium, Then KMnO4 is convert into Mn2 +,C2O4- 2 into CO2 and Cl- into Cl2 . The moles ratio of [MnO4- 2: C2 O4- 2] and [MnO4- 2: HCl] are respective balanced chemical equations are, respectively. (A) 1:5 and 2:5 (B) 2:5 and 1:8 (C) 2:5 and 1:5 (D) 5:2 and 1:8

Tardigrade Admin · Accepted Answer

16H++2MnO4-+5C2O42 - arrow 2Mn+ 2+10CO2+8H2O MnO4-:C2O42 -=2:5 2KMnO4+16HCl arrow 2KCl+2MnCl2+5Cl2+8H2O MnO4-:HCl=2:16=1:8

$1 : 5$ and $2 : 5$

$2 : 5$ and $1 : 8$

$2 : 5$ and $1 : 5$

$5 : 2$ and $1 : 8$

$16 H^{+} + 2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} \to 2 M n^{+ 2} + 10 C O_{2} + 8 H_{2} O$
$M n O_{4}^{-} : C_{2} O_{4}^{2 -} = 2 : 5$
$2 K M n O_{4} + 16 H Cl \to 2 K Cl + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O$
$M n O_{4}^{-} : H Cl = 2 : 16 = 1 : 8$

Q. When KMnO4​ reacts with oxalic acid and HCl separately in acidic medium, Then KMnO4​ is convert into Mn2+,C2​O4−2​ into CO2​ and Cl− into Cl2​ . The moles ratio of [MnO4−2​:C2​O4−2​] and [MnO4−2​:HCl] are respective balanced chemical equations are, respectively.

1:5 and 2:5

2:5 and 1:8

2:5 and 1:5

5:2 and 1:8

16H++2MnO4−​+5C2​O42−​→2Mn+2+10CO2​+8H2​O MnO4−​:C2​O42−​=2:5 2KMnO4​+16HCl→2KCl+2MnCl2​+5Cl2​+8H2​O MnO4−​:HCl=2:16=1:8

$1 : 5$ and $2 : 5$

$2 : 5$ and $1 : 8$

$2 : 5$ and $1 : 5$

$5 : 2$ and $1 : 8$

$16 H^{+} + 2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} \to 2 M n^{+ 2} + 10 C O_{2} + 8 H_{2} O$
$M n O_{4}^{-} : C_{2} O_{4}^{2 -} = 2 : 5$
$2 K M n O_{4} + 16 H Cl \to 2 K Cl + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O$
$M n O_{4}^{-} : H Cl = 2 : 16 = 1 : 8$