When hot aqueous NaOH reacts with Cl2 and gives self oxidised and reduce product in which Cl are in different oxidation states. If the oxidation state of Cl in one product is -1 then what will be oxidation state of Cl in another product is +------.

Question

When hot aqueous NaOH reacts with Cl2 and gives self oxidised and reduce product in which Cl are in different oxidation states. If the oxidation state of Cl in one product is -1 then what will be oxidation state of Cl in another product is +------. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Chlorine reacts with hot and concentrated solution of caustic soda

(N a O H)

to give sodium chloride, sodium chlorate and water as the product.

6 N a O H + 3 C l_{2} \to 5 N a Cl + N a Cl O_{3} + 3 H_{2} O

Oxidation state of chlorine in chloride ion is

- 1

and in other product is +5.

Q. When hot aqueous NaOH reacts with Cl2​ and gives self oxidised and reduce product in which Cl are in different oxidation states. If the oxidation state of Cl in one product is −1 then what will be oxidation state of Cl in another product is +------.

Chlorine reacts with hot and concentrated solution of caustic soda (NaOH) to give sodium chloride, sodium chlorate and water as the product. 6NaOH+3Cl2​→5NaCl+NaClO3​+3H2​O Oxidation state of chlorine in chloride ion is −1 and in other product is +5.

Q. When hot aqueous $N a O H$ reacts with $C l_{2}$ and gives self oxidised and reduce product in which $Cl$ are in different oxidation states.
If the oxidation state of $Cl$ in one product is $- 1$ then what will be oxidation state of $Cl$ in another product is +------.

Chlorine reacts with hot and concentrated solution of caustic soda $(N a O H)$ to give sodium chloride, sodium chlorate and water as the product.
$6 N a O H + 3 C l_{2} \to 5 N a Cl + N a Cl O_{3} + 3 H_{2} O$
Oxidation state of chlorine in chloride ion is $- 1$ and in other product is +5.