When heated, ammonium carbamate decomposes as follows NH4COONH2(.s.)leftharpoons2NH3(.g.)+CO2(.g.) At a certain temperature, the equilibrium pressure of the system is 0.318 atm, Kp for the reaction is

Question

When heated, ammonium carbamate decomposes as follows NH4COONH2(.s.)leftharpoons2NH3(.g.)+CO2(.g.) At a certain temperature, the equilibrium pressure of the system is 0.318 atm, Kp for the reaction is (A) 0.128 (B) 0.146 (C) 4.76× 10- 3 (D) 2.24× 10- 2

Tardigrade Admin · Accepted Answer

undersetE q . p r e s s u r eN H4 C O O N H2 (. s .)leftharpoons underset2 P2 N H3 (. g .)+ undersetPC O2 (. g .) 3P=0.318 P=0.106 PN H3=2× 0.106=0.212 PC O2=0.106 kp=PN H32.PC O2 =0.212× 0.212× 0.106=0.00476 =4.76× 10- 3

Q. When heated, ammonium carbamate decomposes as follows

$N H_{4} COON H_{2} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)$

At a certain temperature, the equilibrium pressure of the system is 0.318 atm, $K_{p}$ for the reaction is

$0.128$

$0.146$

$4.76 \times 1 0^{- 3}$

$2.24 \times 1 0^{- 2}$

$Eq . p ress u re N H_{4} COON H_{2} (s) ⇌ 2 P 2 N H_{3} (g) + P C O_{2} (g)$

$3 P = 0.318$

$P = 0.106$

$P_{N H_{3}} = 2 \times 0.106 = 0.212$

$P_{C O_{2}} = 0.106$

$k_{p} = P_{N H_{3}}^{2} . P_{C O_{2}}$

$= 0.212 \times 0.212 \times 0.106 = 0.00476$

$= 4.76 \times 1 0^{- 3}$

Q. When heated, ammonium carbamate decomposes as follows NH4​COONH2​(s)⇌2NH3​(g)+CO2​(g) At a certain temperature, the equilibrium pressure of the system is 0.318 atm, Kp​ for the reaction is

0.128

0.146

4.76×10−3

2.24×10−2