When HCl gas is passed into water, it gives a solution which contains 30 % HCl by mass. The density of the resultant solution is 1.095 g mL -1. The molarity of the solution is M.

Question

When HCl gas is passed into water, it gives a solution which contains 30 % HCl by mass. The density of the resultant solution is 1.095 g mL -1. The molarity of the solution is M. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

30 % HCl by mass means 30 g of HCl in 100 g of solution. The density of the solution is 1.095 g mL -1. Hence, the volume of the solution =(100/1.095) =91.32 mL Molarity =(30 × 1000/36.5 × 91.32)=9 M

Q. When $H Cl$ gas is passed into water, it gives a solution which contains $30% H Cl$ by mass. The density of the resultant solution is $1.095 g m L^{- 1}$ . The molarity of the solution is_______ $M$ .

$30% H Cl$ by mass means $30 g$ of $H Cl$ in $100 g$ of solution.
The density of the solution is $1.095 g m L^{- 1}$ .
Hence, the volume of the solution $= \frac{100}{1.095}$
$= 91.32 m L$
Molarity $= \frac{30 \times 1000}{36.5 \times 91.32} = 9 M$

Q. When HCl gas is passed into water, it gives a solution which contains 30%HCl by mass. The density of the resultant solution is 1.095gmL−1. The molarity of the solution is_______ M.

30%HCl by mass means 30g of HCl in 100g of solution. The density of the solution is 1.095gmL−1. Hence, the volume of the solution =1.095100​ =91.32mL Molarity =36.5×91.3230×1000​=9M

Q. When $H Cl$ gas is passed into water, it gives a solution which contains $30% H Cl$ by mass. The density of the resultant solution is $1.095 g m L^{- 1}$ . The molarity of the solution is_______ $M$ .

$30% H Cl$ by mass means $30 g$ of $H Cl$ in $100 g$ of solution.
The density of the solution is $1.095 g m L^{- 1}$ .
Hence, the volume of the solution $= \frac{100}{1.095}$
$= 91.32 m L$
Molarity $= \frac{30 \times 1000}{36.5 \times 91.32} = 9 M$