Question

When chlorine is passed through concentrated solution of $KOH$, the compound formed is

• A. $KlC{O}_4$
• B. $KlC{O}_3$
• C. $KlC{O}_2$
• D. $KlCO$

Answer 1

Answer: (B)

When chlorine is passed through hot concentrated solution of $KOH$, potassium chlorate is formed.
$3C{l}_2+\underset{\text{hot conc}}{6KOH}⟶5KCl+\underset{\text{Potassium chlorate}}{KCl{O}_3}+3H_{2}O$
When chlorine is passed into cold dilute solution of $KOH$, potassium hypochlorite is formed.
$C{l}_2+2KOH⟶KCl+\underset{\text{potassium hypochlorite}}{\mathrm{KClO}}+H_{2}O$