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Q.
When chlorine is passed through concentrated solution of $KOH$, the compound formed is
AMUAMU 2004
Solution:
When chlorine is passed through hot concentrated solution of $KOH$, potassium chlorate is formed.
$3 Cl _{2}+ \underset{\text{hot conc}}{6 KOH} \longrightarrow 5 KCl + \underset{\text{Potassium chlorate}}{KClO _{3}}+3 H _{2} O$
When chlorine is passed into cold dilute solution of $KOH$, potassium hypochlorite is formed.
$Cl _{2}+2 KOH \longrightarrow KCl +\underset{\text{potassium hypochlorite}}{KClO} +H_2O$