When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle x according to the equation 1327 Al + 01 n arrow 1124 Na + x What is x ?

Question

When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle x according to the equation 1327 Al + 01 n arrow 1124 Na + x What is x ? (A) Electron (B) Proton (C) Neutron (D) Alpha- particle

Tardigrade Admin · Accepted Answer

The mass number of x=27+1-24=4 and its atomic number =13+0-11=2. Hence particle x is the helium nucleus, which is called an alpha particle

Q. When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle $x$ according to the equation $_{13}^{27} A l +_{0}^{1} n \to_{11}^{24} N a + x$
What is $x$ ?

Electron

Proton

Neutron

Alpha- particle

The mass number of $x = 27 + 1 - 24 = 4$ and its atomic number $= 13 + 0 - 11 = 2.$
Hence particle $x$ is the helium nucleus, which is called an alpha particle

Q. When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle x according to the equation 1327​Al+01​n→1124​Na+x What is x ?