Q.
When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle $x$ according to the equation ${ }_{13}^{27} Al +{ }_{0}^{1} n \rightarrow{ }_{11}^{24} Na + x$
What is $x$ ?
NTA AbhyasNTA Abhyas 2022
Solution:
The mass number of $x=27+1-24=4$ and its atomic number $=13+0-11=2.$
Hence particle $x$ is the helium nucleus, which is called an alpha particle
Hence particle $x$ is the helium nucleus, which is called an alpha particle