When a uranium isotope 23592 U is bombarded with a neutron, it generates 8936 Kr, three neutrons and :

Question

When a uranium isotope 23592 U is bombarded with a neutron, it generates 8936 Kr, three neutrons and : (A) 14456 Ba (B) 9140 Zr (C) 10136 Kr (D) 10336 Kr

Tardigrade Admin · Accepted Answer

23592U + 10n arrow 8936Kr+3 10n+XXA 92+0=36+Z ⇒ Z=56 235+1=89+3+A ⇒ A=144 So, 14456Ba is generated

Q. When a uranium isotope $_{9}^{235} 2 U$ is bombarded with a neutron, it generates $_{36}^{89} Kr$ , three neutrons and :

$_{56}^{144} B a$

$_{40}^{91} Z r$

$_{36}^{101} Kr$

$_{36}^{103} Kr$

$_{92}^{235} U +_{0}^{1} n \to_{36}^{89} Kr + 3_{0}^{1} n + X_{X}^{A}$
$92 + 0 = 36 + Z$
$\Rightarrow Z = 56$
$235 + 1 = 89 + 3 + A$
$\Rightarrow A = 144$
So, $_{56}^{144} B a$ is generated

Q. When a uranium isotope 9235​2U is bombarded with a neutron, it generates 3689​Kr, three neutrons and :

56144​Ba

4091​Zr

36101​Kr

36103​Kr