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  4. When a uranium isotope 23592 U is bombarded with a neutron, it generates 8936 Kr, three neutrons and :

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Q. When a uranium isotope $^{235}_92 U$ is bombarded with a neutron, it generates $^{89}_{36} Kr$, three neutrons and :

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Solution:

$^{235}_{92}U + ^{1}_{0}n \rightarrow ^{89}_{36}Kr+3 ^{1}_{0}n+X_{X}^{A}$
$92+0=36+Z$
$\Rightarrow Z=56$
$235+1=89+3+A$
$\Rightarrow A=144$
So, $^{144}_{56}Ba$ is generated