When a system is taken from state i to state f along the path iaf , it is found that Q = 50 cal and W = 20 cal. Along path ibf Q = 36 cal. W along the path ibf is

Question

When a system is taken from state i to state f along the path iaf , it is found that Q = 50 cal and W = 20 cal. Along path ibf Q = 36 cal. W along the path ibf is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6ee637704f6cf1c2763a0cbe5e23cfa2-.png" /> (A)  6 cal (B)  16 cal (C)  66 cal (D)  14 cal

Tardigrade Admin · Accepted Answer

From first law of thermodynamics, Q=Δ U+W For path iaf, 50=Δ U+20 ∴ Δ U= Uf-Ui=30 cal For path i b f, Q=Δ U+W or W=Q-Δ U =36-30=6 cal

Q. When a system is taken from state $i$ to state $f$ along the path $ia f$ , it is found that $Q = 50$ cal and $W = 20$ cal. Along path $ib f Q = 36$ cal. $W$ along the path $ib f$ is

$6$ cal

$16$ cal

$66$ cal

$14$ cal

From first law of thermodynamics,
$Q = Δ U + W$
For path $ia f$ ,
$50 = Δ U + 20$
$∴ Δ U = U_{f} - U_{i} = 30 c a l$
For path $ib f$ ,
$Q = Δ U + W$
or $W = Q - Δ U$
$= 36 - 30 = 6 c a l$

Q. When a system is taken from state i to state f along the path iaf , it is found that Q=50 cal and W=20 cal. Along path ibfQ=36 cal. W along the path ibf is

6 cal

16 cal

66 cal

14 cal