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  4. When a system is taken from state i to state f along the path iaf , it is found that Q = 50 cal and W = 20 cal. Along path ibf Q = 36 cal. W along the path ibf is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/6ee637704f6cf1c2763a0cbe5e23cfa2-.png />

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Q. When a system is taken from state $ i $ to state $ f $ along the path $ iaf $ , it is found that $ Q = 50 $ cal and $ W = 20 $ cal. Along path $ibf\, Q = 36 $ cal. $ W $ along the path $ ibf $ is
image

UPSEEUPSEE 2010Thermodynamics

Solution:

From first law of thermodynamics,
$Q=\Delta U+W$
For path $iaf$,
$50=\Delta U+20$
$\therefore \Delta U= U_{f}-U_{i}=30\, cal$
For path $i b f$,
$Q=\Delta U+W$
or $W=Q-\Delta U$
$=36-30=6\, cal$