When a system is taken from state 1 to 2 along the path 1 a 2 it absorbs 50 cal of heat and work done is 20 cal. Along the path 1 b 2, Q=36 cal. What is the work done along 1 b 2 ?

Question

When a system is taken from state 1 to 2 along the path 1 a 2 it absorbs 50 cal of heat and work done is 20 cal. Along the path 1 b 2, Q=36 cal. What is the work done along 1 b 2 ? (A) 56 cal (B) 66 cal (C) 16 cal (D) 6 cal

Tardigrade Admin · Accepted Answer

d Q=d u +d W or Q=(u2-u1)+W W=Q1 b 2-(u2-u1) or Q1 b 2-W=u2-u1=36-30=6 cal

Q. When a system is taken from state 1 to 2 along the path $1 a 2$ it absorbs $50 c a l$ of heat and work done is $20 c a l$ . Along the path $1 b 2, Q = 36 c a l$ . What is the work done along $1 b 2 ?$

56 cal

66 cal

16 cal

6 cal

$d Q = d u + d W$ or $Q = (u_{2} - u_{1}) + W$
$W = Q_{1 b 2} - (u_{2} - u_{1})$
or $Q_{1 b 2} - W = u_{2} - u_{1} = 36 - 30 = 6 c a l$

Q. When a system is taken from state 1 to 2 along the path 1a2 it absorbs 50cal of heat and work done is 20cal. Along the path 1b2,Q=36cal. What is the work done along 1b2?