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Q. When a system is taken from state 1 to 2 along the path $1 a 2$ it absorbs $50\, cal$ of heat and work done is $20\, cal$. Along the path $1 b 2,\, Q=36\, cal$. What is the work done along $1 b 2 ?$Physics Question Image

Thermodynamics

Solution:

$d Q=d u +d W$ or $Q=\left(u_{2}-u_{1}\right)+W$
$W=Q_{1 b 2}-\left(u_{2}-u_{1}\right)$
or $Q_{1 b 2}-W=u_{2}-u_{1}=36-30=6\, cal$