When a proton is accelerated from rest through a potential difference of 500 volt, its kinetic energy is

Question

When a proton is accelerated from rest through a potential difference of 500 volt, its kinetic energy is (A) 1840×10-3 electron volt (B) 1840 electron volts (C) 1840×10+3 electron volt (D) None of the above.

Tardigrade Admin · Accepted Answer

Kinetic energy acquired = charge x potential difference = ( 1.6 × 10-19 × 500) J = 500 eV .

Q. When a proton is accelerated from rest through a potential difference of $500 v o lt$ , its kinetic energy is

$1840 \times 1 0^{- 3}$ electron volt

1840 electron volts

$1840 \times 1 0^{+ 3}$ electron volt

None of the above.

Kinetic energy acquired = charge x potential difference
= $(1.6 \times 1 0^{- 19} \times 500)$ J = 500 eV .

Q. When a proton is accelerated from rest through a potential difference of 500volt, its kinetic energy is

1840×10−3 electron volt