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  4. When a proton is accelerated from rest through a potential difference of 500 volt, its kinetic energy is

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Q. When a proton is accelerated from rest through a potential difference of $500\, volt$, its kinetic energy is

Electrostatic Potential and Capacitance

Solution:

Kinetic energy acquired = charge x potential difference
= $( 1.6 \times 10^{-19} \times 500) $ J = 500 eV .