When a projectile is fired with initial velocity u at an angle of projection 6, then its range is R. If the initial velocity is doubled at same angle of projection, then the new range will be

Question

When a projectile is fired with initial velocity u at an angle of projection 6, then its range is R. If the initial velocity is doubled at same angle of projection, then the new range will be (A)  R  (B)  (R/2)  (C)  2R  (D)  4R

Tardigrade Admin · Accepted Answer

The range of a projectile, R=(u2 sin 2θ /g) ⇒ R propto u2 So, if the velocity is doubled then range will becomes 4 times.

Q. When a projectile is fired with initial velocity u at an angle of projection 6, then its range is R. If the initial velocity is doubled at same angle of projection, then the new range will be

$R$

$\frac{R}{2}$

$2 R$

$4 R$

The range of a projectile, $R = \frac{u ^{2} s i n 2 θ}{g}$ $\Rightarrow$ $R \propto u^{2}$ So, if the velocity is doubled then range will becomes 4 times.

Q. When a projectile is fired with initial velocity u at an angle of projection 6, then its range is R. If the initial velocity is doubled at same angle of projection, then the new range will be

R

2R​

2R

4R

The range of a projectile, R=gu2sin2θ​ ⇒ R∝u2 So, if the velocity is doubled then range will becomes 4 times.

$R$

$\frac{R}{2}$

$2 R$

$4 R$

The range of a projectile, $R = \frac{u ^{2} s i n 2 θ}{g}$ $\Rightarrow$ $R \propto u^{2}$ So, if the velocity is doubled then range will becomes 4 times.