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Q. When a projectile is fired with initial velocity u at an angle of projection 6, then its range is R. If the initial velocity is doubled at same angle of projection, then the new range will be

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Solution:

The range of a projectile, $ R=\frac{{{u}^{2}}\sin 2\theta }{g} $ $ \Rightarrow $ $ R\propto {{u}^{2}} $ So, if the velocity is doubled then range will becomes 4 times.