Q.
When a potential difference of 103V is applied between A and B , a charge of 0.75mC is stored in the system of capacitors as shown.The value of C is (inμF)
4921
217
KCETKCET 1999Electrostatic Potential and Capacitance
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Solution:
In the given circuit, 2μF and 2μF capacitors are in series CS=2+22×2=1μF
equivalent circuit will be
Now CμF and 1μF are in parallel which is in series with 1μF ∴Ceff =(C+1)+1(C+1)×1=C+2C+1
Given, q=0.75×10−3C=750×10−6C,V=103V
So, Ceff =Vq ⇒C+2C+1=103750×10−6 =750×10−3F=0.75μF ⇒0.75=C+2C+1 ⇒43=C+2C+1 ⇒3C+6=4C+4 ⇒C=2μF