When a positive q charge is taken from lower potential to a higher potential point, then its potential energy will

Question

When a positive q charge is taken from lower potential to a higher potential point, then its potential energy will (A) decrease (B) increases (C) remain unchanged (D) become zero

Tardigrade Admin · Accepted Answer

Δ P . E .= Work done by external agent =(Vf q-Vi q) Vf > Vi ⇒ Δ P . E .>0 i.e. P.E. will increase

Q. When a positive $q$ charge is taken from lower potential to a higher potential point, then its potential energy will

decrease

increases

remain unchanged

become zero

$Δ P . E . =$ Work done by external agent
$= (V_{f} q - V_{i} q)$
$V_{f} > V_{i} \Rightarrow Δ P . E . > 0 i . e . P . E .$ will increase

Q. When a positive q charge is taken from lower potential to a higher potential point, then its potential energy will